Optimal Scheduling of Multiproduct Pipelines in Networks with

Jul 28, 2017 - This paper presents a new continuous-time mixed-integer linear programming formulation for scheduling pipeline systems transporting liq...
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Optimal Scheduling of Multiproduct Pipelines in Networks with Reversible Flow Pedro Miguel Castro Ind. Eng. Chem. Res., Just Accepted Manuscript • DOI: 10.1021/acs.iecr.7b01685 • Publication Date (Web): 28 Jul 2017 Downloaded from http://pubs.acs.org on August 1, 2017

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Industrial & Engineering Chemistry Research

Optimal Scheduling of Multiproduct Pipelines in Networks with Reversible Flow Pedro M. Castro,1 Centro de Investigação Operacional, Faculdade de Ciências, Universidade de Lisboa, 1749-016 Lisboa, Portugal Abstract This paper presents a new continuous-time mixed-integer linear programming formulation for scheduling pipelines systems transporting liquid products. It is a generic formulation with respect to the structure of the network (nodes and connecting segments form the building blocks), and to the direction of flow that can change as many times as required. Nodes are connected to one or more pipeline segments and external interactions with refineries (at a constant rate) and local markets may be included for better inventory control. To ensure a computationally efficient formulation by design, constraints with binary and continuous variables were first written as disjunctions and then convex-hull reformulated. It is validated through the solution of six benchmark problems from the literature involving straight pipelines with reversible flow as well as tree-like and mesh structures with unidirectional flow. The schedules obtained by the optimization reflect, in most cases, a better utilization of the pipeline capacity.

1

Corresponding author. E-mail: [email protected].

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INTRODUCTION Pipelines are extensively used by the petroleum industry for transporting crude oil from wells to

refineries and for sending refined products (e.g. gasoline, diesel, jet fuel) from refineries to distribution centers serving local markets. In 2013, pipeline operators in the U.S. delivered 15 billion barrels, for a total mileage over 192,0001. It is thus no surprise that different research groups around the world2-10 have studied this problem over the last 15 years. The emphasis has been on mathematical programming2-9 but approaches using heuristics10-11,14, constraint programming12, discrete-event simulation13, taboo13 and variable neighborhood search14, simulated annealing10,14 and Markov chains14, can also be found. At the very least, pipeline scheduling involves finding the timing of product injections from an input to an output node. Product sequence, size and pumping flowrate may be given but you may want to find the optimal values according to some economic criterion. Pipelines are connected to storage tanks that also receive materials from refineries and ship them to local markets. Storage tanks are usually modelled in an aggregate way, with minimum and maximum capacity constraints for each product, but can also be modelled in detail to account for settling periods5 and other operational rules. Pipeline scheduling problems can be very complex to solve, starting with system configuration. While one may hope to get valuable information from a model with a single input, single output node and detailed inventory management of the tank farm5, simplifications are needed when moving towards problems with multiple output nodes. These can be arranged in a straight line2-3,9, or in a tree-like structure with branches8,15. We can also find straight systems with multiple input and output nodes10, possibly with dual purpose nodes that can act as input nodes during some periods and as output nodes in others16-19. In the most complex configuration, we have a pipeline network4,7,12,14,20-21 with nodes and pipeline segments as the building blocks. It is the purpose of this paper to develop a modular formulation capable of handling all possible configurations, in the spirit of our previous work for treelike systems6. Compared to the work of Cafaro and Cerdá20, which represent a network as an integrated set of single lines, a line is now 2 Environment ACS Paragon Plus

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divided into as many segments as the number of intermediate nodes (plus one). The advantage, as 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

will be seen later, results from the rigorous handling of minimum and maximum flowrate constraints that naturally change across a line whenever there are injections/withdrawals from intermediate nodes. Nodes can be of different types and can be linked to a storage system that interacts dynamically with a refinery and a local market. The proposed model is a generalization of our recent work for straight pipelines19 and can be classified as a product-centric model2,4,6-7,12,14 since there is no need to postulate a set of batches for modelling the movement of materials inside the pipeline. The main novelty is that it is now possible to change the flow direction, as many times as required. Models allowing for reversible flow are far less common than their unidirectional counterparts. The first work is due to Magatão et al.4 who have used a discrete time and volume formulation that assumes a fixed pumping rate for moving products in a line connecting a refinery to a harbor. Later, the same authors12 switch to continuous-time while still discretizing the pipeline volume in fixed packs of 1800 m3 and keeping the constraint of a single flow reversal throughout the planning horizon. The discrete-volume formulation of Herran et al.7 considers a single segment with reversible flow in a network with seven segments and seven nodes. The model of Cafaro and Cerdá22 uses a continuous time and volume representation but is limited to a single line with two terminal nodes (and intermediate output nodes). Continuous-volume formulations3,5-6,8-9,15-20 allow for multiple products/batches per segment and keep track of their exact location by using two sets of coordinates (left and right). By converting products into batches, batch-centric formulations allow for multiple batches of a product in the same segment. The same is not true for their product-centric counterparts6,19 (including the model proposed in this work), which also need to be able to reset coordinates to allow for product re-entry. The novelty in this work, compared to ref. 19, is that we now allow re-entry on both sides of a segment, looking at the value of the left or right coordinate to decide if a product can enter in the next time slot.

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While able to cover a wider range of solutions, batch-centric formulations3,5,8-11,15-18,20,22 have their 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

own limitations. The first is associated to the postulation of the total number of batches as well as to the characterization of the initial pipeline status as a sequence of batch elements. They can be viewed as tuning parameters that add up to the number of events (also called pumping runs) that compose the single continuous-time grid, recommended when dealing with continuous processes6,23. It may not be that much of an issue in systems with a single input node, but several combinations may arise when dealing with intermediate input nodes18-19. In systems with reversible flow, Cafaro and Cerdá22 divide new batches into direct and reverse flow, testing 21 cases and observing major differences in solution quality and computational time (up to two orders of magnitude). The second limitation is related to handling forbidden product sequences. Since there may be batches that at some point (intermediate withdrawal) become empty, forbidding sequences based on the batchproduct assignment variables of consecutive batches may not be enough. Overall, there is no clear winner between batch- and product-centric formulations19. In the current paper, we also generalize the rigorous forbidden sequence constraints from unidirectional19 to reversible flow. The rest of the paper is organized as follows. After the problem statement in section 2, we solve a motivating example in section 3. It features a central node connected to three terminal nodes by three segments and three products. Each product is supplied by a single node and needs to be delivered to the other two, forcing the direction of flow to be reversed. A brief description of the underlying continuous-time representation is the subject of section 4, before the actual formulation in section 5. Section 6 concerns the computational studies, which include benchmark problems with different pipeline configurations. Finally, the conclusions are given in section 7. 2.

PROBLEM STATEMENT

This paper deals with a multiproduct pipeline system consisting of a set of nodes  ∈  arranged

in a network. Nodes can be of different types and will typically be linked to a storage system with , , , given minimum , , maximum , and initial capacity , (m3). These are aggregate values

for every product  ∈ , meaning that multiple storage tanks may be involved. Storage tanks may in

, turn be associated to a refinery, receiving material at a flowrate , (m3/h) that is assumed to be

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constant throughout the duration of the time horizon. They may also be connected to a local market. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

, (m3) can be met with multiple supplies, at maximum supply In such case, product demand , , flowrates , (m3/h), to allow for better inventory control. Otherwise, the amount in storage at

the end must exceed demand. Some nodes can inject material from the storage tanks into the pipeline

, , , , ] (m3/h). Similarly, the receiving flowrate must be within at flowrates in the range [,

, , [, , , ]. The volume entering/leaving the node from/into the pipeline is also bounded

[, , , ] (m3), being assumed that , > 0.

Nodes are connected by segments ! ∈ " of volume # (m3). Segments can change their direction

of flow, referred to as either left-to-right (LR) or right-to-left (RL), operating at flowrates in the

range [#,$ , #,$ ] or [#,$ , #,$ ] (m3/h). The different values reflect the fact that the

movement is usually favored in one direction due to the terrain profile22. The initial status of all

, segments is also assumed given in terms of the amounts #, (m3) and location of all products inside. $, , , $, , The latter is known with either the left %#, or right %#, coordinates, since %#, = %#, + #, .

Specific product sequences can be forbidden. These are specified in subsets  , with ´ ∈ 

meaning that ´ cannot enter a segment after .

The objective is to find the volumes and timing of product injections from input nodes and

deliveries to output nodes that meet demand in the shortest time possible, while respecting flowrate and storage capacity limits, and forbidden product sequences. Objective functions other than makespan minimization are straightforward to implement19. 3.

MOTIVATING EXAMPLE To illustrate the problem of scheduling a multiproduct pipeline with reversible flow consider the

example in Figure 1. It consists of a central node (N2) connecting three dual purpose terminal nodes (N1, N3-N4). There are three products (P1-P3) in the system and each terminal node supplies one product and needs to receive the other two. The initial status of the pipeline consists of P1 in segment S1 and P2 in segments S2 and S3. The segment volumes # are 5000, 4000 and 3000 m3 and the operating flowrate in all segments must be in the range [20, 200] m3/h (in both directions). 5 Environment ACS Paragon Plus

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Supply: P1 30000 m3 Demand: P2 5000 m3 P3 5000 m3 N1

# ∈ [20,200] *3 /P1 5000

N3

N2

Segment S1 ./ = 0 -

N4

Supply: P2 15000 m3 Demand: P1 5000 m3 P3 5000 m3 Supply: P3 15000 m3 Demand: P1 5000 m3 P2 5000 m3

Figure 1. Motivating example.

Figure 2. Best-found solution in terms of makespan minimization for motivating example. The best-found solution with respect to the shortest time needed to meet product demand (195 h), requires a minimum of ten different periods of operation. The optimal schedule is given in Figure 2 and a few aspects are worth highlighting: (i) the flow direction is reversed in all segments, once in segments S1 and S3 and twice in segment S2; (ii) all segments are idle at some point in time; (iii) an 6 Environment ACS Paragon Plus

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output node can receive material as a consequence of simultaneous injections from multiple input 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

nodes that may involve different products (in the second row, first column of Figure 2, the injection of product P1 at N1 and P3 at N4 is responsible for sending P2 to N3); it also happens in the third row, second column; the two cases have in common the delivery of a product that is not needed; (iv) the minimum demands are exactly met; (v) product P2, initially in segments S2 and S3, is used to fulfil the 5000 m3 demand in N4, backtracks to N3 to make it possible for the node to receive P1 and P3, returning later to S2 to meet the demand of P2 in N1; (vi) segments typically end a period filled with a single product, the exception being the lowest capacity segment S3, which holds P1 and P3 from ]50, 75[ h; (vii) the operating flowrate is the maximum whenever there are just two active segments, with the lowest value of 40 m3/h in segment S3 being above the specified minimum of 20. 4.

TIME REPRESENTATION Scheduling models can be classified according to different criteria, with the underlying time

representation being one of the most important24. Earlier works for pipeline scheduling3,6 have shown that a continuous-time representation relying on a single grid significantly improved computational performance compared to a discrete-time representation2. It is the preferred choice by the large majority of research groups working in pipeline scheduling, sometimes disguised under the term pumping operation15,25, and is also used in this paper. Readers interested in replacing the continuous with a discrete-time representation may find useful the recent paper26 for scheduling the transfer of crude oil from marine vessels to the distillation units.

The single time grid given in Figure 3 is made of 1 ∈ . event points. The first, corresponds to the

origin, ./ = 0, while the last, bounded by the given time horizon -, defines the makespan, eq 1. The

exact location of event points in the grid is going to be determined by the optimization, through variables .2 that respect eq 2. Variables 32 hold the duration of the time slot and facilitate the writing

of the minimum and maximum flowrate constraints. Note that solution quality and computational

performance are highly dependent on |.| and that global optimality can only be guaranteed as

|.| → ∞. The iterative search procedure used in practice is to keep solving the problem, following single increments in |.|, until the solution stops improving. Such schedules will be assumed optimal. 7 Environment ACS Paragon Plus

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time slot 2

slot |T|-2

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Time grid 2 1 Variables

T1

3

|T|-2

|T|-1 t=|T|

event points

L1

T2

L2

T3

T|T|-2

L|T|-2

T|T|-1

T|T| L|T|-1

Figure 3. The mathematical formulation uses a continuous-time representation with a single grid.

min .|:|

(1)

.2;/ = .2 + 32 ∀1 ≠ |.| 5.

(2)

MATHEMATICAL FORMULATION Any pipeline system can be seen as a collection of nodes and segments and so it is convenient to

divide the product-centric formulation in two parts. The new scheduling formulation has been derived using Generalized Disjunctive Programming27-29 which, by showing the model constraints in their simplest form, helps to reduce the modelling burden associated to such complex system. You will see that disjunctions feature constraints with mostly one variable (given in upper case to better distinguish from lower-case parameters) to ensure efficiency of the resulting convex hull reformulation29-30. 5.1. Nodes The different types of nodes that can appear in a pipeline system are given in Figure 4. All nodes

have a storage system, except junction nodes  ∈  > that do not. The volumetric balance for the

storage system associated to non-junction node  ∈ \ > is given in eq 3 and illustrated in Figure 5.

It states that the difference in the volume of product  between event points 1 and 1 − 1 (or the

, initial state) is equal to the volume entering the tanks from the pipeline (B,,2C/ ) and associated

, , refinery (, 32 ), minus the volume leaving the tanks to the pipeline (B,,2 ) and local markets

, , (B,,2 ). Recall that we assume a constant inlet flowrate from the refinery , to non-junction

node  ∈   throughout the duration of the time horizon. In contrast, the amount sent to local markets by non-junction node  ∈   can vary between time slots, if the maximum flowrate

, , is not exceeded, see eq 4. Eq 5 reflects the lower and upper bounds on storage capacity.

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, S,,2

IN

 D,,2

N

, B,,2

Output

, S,,2

N

Dual purpose

B, ,,2

, S,,2 , B,,2

N

OUT

Input

IN

Node type

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OUT

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Terminal

Intermediate

Junction

N

N

N

, S,,2

B, ,,2

Subset

R

T

U

:



>

Connecting segments

≥1

≥1

≥1

=1

≥2

≥3

Figure 4. Nodes in a pipeline system. ,  D,,2 = , E

, B,,2C/ E

∈ L

2F/

,  + D,,2C/ + B,,2C/ E

∀ ∈ \ > ,  ∈  , 1

∈G ∪ I

, + , 32 E

∈J

, , B,,2 M , 32 ∀ ∈   ,  ∈  , 1 ≠ |.|

, ,  M D,,2 M , ∀ ∈ \ > ,  ∈  , 1 ,

, − B,,2C/ E

∈ K ∪I

− (3) (4) (5)

Product demand is enforced by either eq 6 or 7. If storage capacity is a limiting aspect, it is better

to consider multiple supplies to local markets. In eq 6, the sum of all volumes leaving the tanks must

, be equal to the total demand , . Otherwise, there is no need to consider local markets explicitly

( ∉   ), being sufficient to enforce that the volume at the final event point is greater than the demand.

, , ∑2P|:| B,,2 = , ∀ ∈   ,  ∈  ,  D,,|:| Q , ∀ ∉   ,  ∈ 

Figure 5. Volumes entering and leaving a node.

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The volumetric balance for node  during slot 1 is illustrated in Figure 5 and given in eq 8.

Without loss of generality, we consider that the node can either be connected to the right or left-end of a segment. In the former case, the volume entering the node from segment ! ∈ " is the one

, leaving the segment on the right, B#,,2 , due to a left to right direction of flow. In the latter case, the ,$ volume entering the node from segment !´ ∈ "$ is the one leaving the segment on the left, B#´,,2 ,

due to a right to left direction of flow. For the volumes leaving the node and entering the pipeline,

one must consider the inlet flows on the right of segment ! and on the left of segment !´. Note that

subsets # , # , #$ and #$ hold the products that can leave/enter a segment on its right and left end.

, E B,,2

, B,,2 E

∈K ∪I

∈G ∪I

, + ∑#∈\J VB#,,2 E

,$ + ∑#´∈\^(B#´,,2 E

∈WXJY

^Z ∈WX´

, − B#,,2 E

,$ − B#´,,2 E

∈WXJZ

^Y ∈WX´

[=

) ∀,  ∈  , 1 ≠ |.|

(8)

5.1.1. Input Node Both single purpose input nodes and dual purpose nodes can inject material into the pipeline. Let

, , the binary variable S,,2 = 1 if node  is pumping product  during slot 1 and S,2 = 1 if no

product is entering the pipeline. In the former case, the transferred volume must belong to the , , , interval [, , , ] while the flowrate (B,,2 /32 ) must lie within [, , , ]. In the

latter case, the transferred volume of all products is set to zero and the constraint on the slot duration

variable 32 is relaxed so that an active operation can set its value.

, S,,2 c f , S,2 , b, M B,,2 M , e e ` gB , = 0 ∀ ∈  h ∀ ∈  R ∪  U , 1 ≠ |.| `b , ,  ,,2 e B,,2 B,,2 C b 3 M ∈W\ b M 3 M e 2 2 , , , a , d

(9)

The logic proposition implicit in the exclusive disjunction in eq 9 generates eq 10. The convex hull reformulation of the constraints leads to eqs 11-12, after combining equations to eliminate

, disaggregated variables and binaries S,2 from the formulation (further details can be found in

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Mostafaei and Castro18 where the equivalent to eq 12 was mistakenly said to be derived from the 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

big-M reformulation; in ref. 18, eq 14 is derived simply by replacing the two terms on the right-hand side of eq 12 with their bounds from eqs 13 and 11). , ∑∈W\ S,,2 M 1 ∀ ∈  R ∪  U , 1 ≠ |.|

, , , , S,,2 M B,,2 M , S,,2 ∀ ∈  R ∪  U ,  ∈  , 1 ≠ |.|

∑∈W\

l,mno i\,j,k

l,qZrst M 32 M ∑∈W\

p\,j

l,mno i\,j,k

l,qZrno p\,j

, + - ∙ (1 − ∑∈W\ S,,2 ) ∀ ∈  R ∪  U , 1 ≠ |.|

(10) (11) (12)

Note that an input node can simultaneously send material to all its connecting pipeline segments only if the same product is involved. 5.1.2. Output Node To generate the constraints for single purpose output nodes or dual purpose nodes, it suffices to change the variables superscript from “in” to “out” and alter the domain. , ∑∈W\ S,,2 M 1 ∀ ∈  T ∪  U , 1 ≠ |.|

, , , , S,,2 M B,,2 M , S,,2 ∀ ∈  T ∪  U ,  ∈  , 1 ≠ |.|

∑∈W\

l,mvwx i\,j,k

l,qYrst M 32 M ∑∈W\

p\,j

l,mvwx i\,j,k

l,qYrno p\,j

, + - ∙ (1 − ∑∈W\ S,,2 ) ∀ ∈  T ∪  U , 1 ≠ |.|

(13) (14) (15)

5.1.3. Terminal Dual Purpose Node By having a single connecting segment, terminal dual purpose nodes become a special case that

can benefit from tighter constraints. Clearly, during slot 1, the node, if active, can either be sending

or receiving material. This is translated into the exclusive disjunction in eq 16 that features auxiliary

, yz{ binary variables S,2 to account for idleness. The convex hull reformulation generates eqs 11 and

14 (no need to update their domain), and eqs 17-19, which replace eqs 10, 12-13 and 15.

, , , yz{ S,,2 S,,2 S,2 c f c f c f , , , b, M B,,2 b, M B,,2 M , e M , e bB,,2 e = 0 ∀ e`b e`b `b e , , , , , e e C b B,,2 B,,2 B,,2 B,,2 C b B = 0 ∀ ,,2 b e ∈W\ b M 32 M , e ∈W\ b , M 32 M , e , a 32 M d , , a , d a , d

∀ ∈  : ∩  U , 1 ≠ |.|

(16)

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, , ∑∈W\(S,,2 + S,,2 ) M 1 ∀ ∈  : ∩  U , 1 ≠ |.|

∑∈W\(

l,mno i\,j,k

l,qZrst +

p\,j

32 M ∑∈W\ (

l,mvwx i\,j,k

l,qYrst p\,j

l,mno i\,j,k

l,qZrno +

p\,j

(17)

) M 32 ∀ ∈  R ∪  U , 1 ≠ |.|

l,mvwx i\,j,k

l,qYrno p\,j

(18)

, , ) + - ∙ }1 − ∑∈W\~S,,2 + S,,2 € ∀ ∈  R ∪  U , 1 ≠ |.| (19)

5.1.4. Intermediate Dual Purpose Node To reduce solution degeneracy, an intermediate dual purpose node should not simultaneously send

and receive a product from its storage system. Thus, sending product  implies that  is not being received (eq 20). Receiving also implies not sending. Both logic propositions can be reformulated29

into eq 21, which is in MILP format. It does not prevent the node to receive one product from a segment while sending another to a different segment during the same slot. , , S,,2 ⟹ ¬S,,2 ∀ ∈   ∩  U ,  ∈  , 1 ≠ |.|

(20)

, , S,,2 + S,,2 M 1 ∀ ∈   ∩  U ,  ∈  , 1 ≠ |.|

(21)

5.2. Segments

Since we are dealing with incompressible fluids, the sum of all volumes inside segment ! must be

equal to the segment volume, as stated by eq 22. The volumetric balance given in eq 23 and illustrated in Figure 6, states that the change in volume of product  is equal to the difference

between incoming and outgoing flows. If the segment is active with left to right flow during slot 1,

,$ , and B#,,2 will be greater than zero for exactly one product (note that the product variables B#,,2

, going in might differ from the one coming out). If the flow is from right to left, it is variables B#,,2

,$ and B#,,2 that may be nonzero.  ∑∈WX D#,,2 = # ∀!, 1  D#,,2 =

, #, E

2F/

,$  + D#,,2C/ + B#,,2C/ E

(22)

∈WX^Z

, + B#,,2C/ E

∈WXJZ

,$ − B#,,2C/ E

∈WX^Y

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, − B#,,2C/ E

∈WXJY

∀!,  ∈ # , 1(23)

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,$ B#,,2

,$ B#,,2

 D#,,2

Segment !

Left

Industrial & Engineering Chemistry Research , B#,,2

, Right B#,,2

Figure 6. Volumes entering and leaving a segment. 5.2.1. Understanding Coordinate Variables The product-centric model of Castro and Mostafaei19 allows a product to re-enter a segment in unidirectional pipelines. The constraints given below are the generalization for reversible flow.

$  Let nonnegative continuous variables ƒ#,,2 and ƒ#,,2 give the left and right coordinates of product

 in segment ! at event point 1. By definition, the right coordinate is equal to the left coordinate plus

the volume inside, eq 24, and both are bounded by the segment volume, eqs 25-26.   $ ƒ#,,2 = ƒ#,,2 + D#,,2 ∀!,  ∈ # , 1

(24)

$ ƒ#,,2 M # ∀!,  ∈ # , 1

(25)

 ƒ#,,2 M # ∀!,  ∈ # , 1

(26)

$,{ y ,{ y Continuous coordinate variables ƒ#,,2C/ and ƒ#,,2C/ give the status of the system prior to the

„ activation of continuous reset variables ƒ#,,2 , see eqs 27-28. Contrary to the case of unidirectional

flow19, they all must now be allowed to assume negative values. In eq 29, the left coordinate of

product  will increase whenever a product ´ ≠  is entering the segment on the left and decrease if

´ is leaving the segment on the left. Similarly, the right coordinate will increase/decrease due to different products leaving/entering on the right. $, $ ƒ#,,2 = %#, E

2F/

,  ƒ#,,2 = %#, E

2F/

$,{ y „ + ƒ#,,2C/ − ƒ#,,2 ∀!,  ∈ # , 1

,{ y „ + ƒ#,,2C/ − ƒ#,,2 ∀!,  ∈ # , 1

$,{ y ,$ $ ƒ#,,2 = ƒ#,,2 + ∑´∈WX :´P(B#,´,2 E

´∈WX^Z

,{ y ,  ƒ#,,2 = ƒ#,,2 + ∑´∈WX :´P(B#,´,2 E

(27) (28)

,$ − B#,´,2 E

´∈WXJY

´∈WX^Y

, − B#,´,2 E

) ∀!,  ∈ # , 1 ≠ |.|

´∈WXJZ

) ∀!,  ∈ # , 1 ≠ |.|

(29) (30)

„ It remains to allow reset variables ƒ#,,2 to be different than zero only if product  is not inside

,#  segment ! at event point 1 (S#,,2 = 0), which is known from the value of variable D#,,2 , see

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1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

disjunction in eq 31. Notice that the constraint also applies to 1 = 1, to let product , initially not

$, , = %#, = 0), to enter either on the left (required inside segment ! (specified by making %#,

$  condition: ƒ#,,/ = 0) or right (ƒ#,,/ = # M #, ). Eq 31 is reformulated into eqs 32-33, where

" $ and " $ are the subset of segments allowing for left-to-right and right-to-left flows, respectively. ,# ¬S#,,2

,# S#,,2

  D#,,2 =0 gD#,,2 h ∀!,  ∈ # , 1 M # h ` g , , „ „ −# E#∈ J^ M ƒ#,,2 M # E#∈ ^J ƒ#,,2 =0

,#  D#,,2 M # S#,,2 ∀!,  ∈ # , 1 ,# ]E −[#, ∙ ~1 − S#,,2

#∈ J^

(31) (32)

,# „ M ƒ#,,2 M [#, ∙ ~1 − S#,,2 ]E

#∈ ^J

∀!,  ∈ # , 1

(33)

The values of the coordinates for a simple example can be found in Figure 7. Notice that the

 $  coordinates for product P3 at event 1 = 2 (ƒ/,W†,‡ = ƒ/,W†,‡ = / = 10000) will allow P3 to enter

the segment on the right during slot 1 = 2 (check first constraint in top-middle term of eq 34),

„ requiring the reset coordinate to be ƒ/,W†,‡ = 5000. Alternatively, if P3 were to enter on the left, the

„ $ optimization would have selected ƒ/,W†,‡ = 15000, to meet the required constraint of ƒ/,W†,‡ =0

(first constraint in top-left term in eq 34).

Figure 7. Values of coordinate variables for a simple example involving reversible flow. 14 Environment ACS Paragon Plus

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5.2.2. Modeling Reversible Flow 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

Let ! ∈ "  be a segment allowing for reversible flow. During slot 1, it must be in exactly one of

three states: (i) active, with flow from left to right; (ii) active, with flow from right to left; (iii) idle.

,$ In case of left to right flow (‰#,2 = 1), exactly one product must be entering the segment on the

,$ = 1) and one product, the same or another, must be leaving the segment on the right left (S#,,2 , (S#,,2 = 1). The product entering on the left, must have its left coordinate equal to zero, while the

right coordinate of the product leaving on the right, must be equal to the segment volume # . The

bounds on the transferred volume and flowrate are like before but the flowrate bounds are now product independent (multiple products may be moving inside) while dependent on the direction of flow (e.g. #,$ , #,$ ), see eq 34.

,$ , In the case of right to left flow (‰#,2 = 1), the product entering on the right (S#,,2 = 1) must

have its right coordinate equal to the segment volume, while the product leaving on the left ,$ (S#,,2 = 1) must have its left coordinate equal to zero.

, yz{ = 1), the constraints on the coordinate and timing variables are If the segment is idle (‰#,2

relaxed, while the transferred volume variables are set to zero for all products.

,$ ,$ ‰#,2 ‰#,2 c f c f , yz{ ‰#,2 ,$ , c f b e b e S S #,,2 #,,2 c f c f $ M # ∀ e b e b e b ƒ#,,2 $   b ƒ#,,2 = 0 e b ƒ#,,2 = # e b e b b ƒ  Q 0 ∀ e b , e b ee #,,2 ,$ , b ` b# b ` b#, M B#,,2 b ,$ e M B#,,2 M #, e e M #, e e b C b ,$ b C b , b B#,,2 = 0 ∀ e ,$ e e , e e B#,,2 ` b ∈WXJZ B#,,2 B#,,2 ` b , b ∈WX^Z b B#,,2 e e e b ee B#,,2 = 0 ∀ ,$ M 32 M ,$ e C b ,$ M 32 M ,$ e b b e # # a# d a # d , b e b e b B#,,2 = 0 ∀ e , ,$ S#,,2 S#,,2 b e b e b ,$ e B#,,2 = 0 ∀ e   $ b` g e b e b ƒ#,,2 = # ƒ#,,2 = 0 h ` g h b C e b C e a 32 M d , , , , ,$ , M B#,,2 M # M B#,,2 M # a∈WXJY # d a∈WX^Y # d

∀! ∈ "  , 1 ≠ |.|

(34)

It is important to highlight that the constraint of no more than one product leaving as a

consequence of a product injection, is not a limitation of the model since it is within a time slot. Multiple products can leave (one after the other) as a consequence of a product injection, it just requires multiple time slots (one per leaving product, see Figure 2). 15 Environment ACS Paragon Plus

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Eq 34 features embedded disjunctions that can be transformed into simple disjunctions and logic 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

propositions using the guidelines in Vecchietti and Grossmann31 (examples of real-world problems tackled by GDP models relying on embedded disjunctions can be found in refs 32-36). The logic proposition of the outer disjunction can be reformulated into eq 35, after eliminating variables , yz{ ‰#,2 .

,$ ,$ ‰#,2 + ‰#,2 M 1 ∀! ∈ "  , 1 ≠ |.|

(35)

The logic propositions relating the binary variables of outer and inner disjunctions lead to eqs 36-

39.

,$ ,$ ‰#,2 = ∑∈WX^Z S#,,2 ∀! ∈ "  , 1 ≠ |.|

(36)

,$ , ‰#,2 = ∑∈WXJY S#,,2 ∀! ∈ "  , 1 ≠ |.|

(37)

,$ , ‰#,2 = ∑∈WXJZ S#,,2 ∀! ∈ "  , 1 ≠ |.|

(38)

,$ ,$ ‰#,2 = ∑∈WX^Y S#,,2 ∀! ∈ "  , 1 ≠ |.|

(39)

The constraints linking the binary and continuous variables can be found in eqs 40-43. Notice that

the information about the direction of flow is part of subsets # and so the constraints also apply to

segments with unidirectional flow.

,$ ,$ ,$ #, S#,,2 M B#,,2 M #, S#,,2 ∀!,  ∈ #$ , 1 ≠ |.|

, , , M B#,,2 M #, S#,,2 ∀!,  ∈ # , 1 ≠ |.| #, S#,,2

, , , #, S#,,2 M B#,,2 M #, S#,,2 ∀!,  ∈ # , 1 ≠ |.|

,$ ,$ ,$ #, S#,,2 M B#,,2 M #, S#,,2 ∀!,  ∈ #$ , 1 ≠ |.|

(40) (41) (42) (43)

The coordinate and timing constraints can also be derived from the isolated inner constraints. There is however a way to reduce their number while making them tighter. For the coordinate constraints, one can use the knowledge that product , during slot 1, can either enter, leave or not be ,$  involved (e.g. S#,,2 = 1). The disjunctions in eqs 44-45 apply to the left and right sides and are

reformulated into eqs 46-47. ,$ S#,,2

,$ S#,,2

,$  S#,,2

Š $ ‹`Š $ ‹`Š $ ‹ ∀!,  ∈ # , 1 ≠ |.| =0 ƒ#,,2 M # ƒ#,,2 = 0 C ƒ#,,2 16 Environment ACS Paragon Plus

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Industrial & Engineering Chemistry Research , S#,,2

, S#,,2

(44)

,  S#,,2

‹ ∀!,  ∈ # , 1 ≠ |.| Š  ‹`Š  ‹`Š  = # ƒ#,,2 Q 0 ƒ#,,2 = # C ƒ#,,2 ,$ $ ƒ#,,2 M # ∙ (1 − S#,,2 E

,  Q # ∙ (S#,,2 E ƒ#,,2

∈WX^Z

∈WXJZ

,$ − S#,,2 E

, + S#,,2 E

∈WX^Y

∈WXJY

(45)

) ∀!,  ∈ # , 1 ≠ |.|

(46)

) ∀!,  ∈ # , 1 ≠ |.|

(47)

For the timing constraints, eq 48 states that there is at most one product entering on the left or right

during slot 1. It leads to eqs 49-50. ,$ ` g B#,,2

C ∈WX^Z

∑(

#,$

m,^no iX,j,k

m,^Jrst Œ

pX

32 M ∑(

M 32 M

∈WX^Z

m,^no iX,j,k

,$ S#,,2

m,^Jrno Œ

pX

+

,$ , h ` g B#,,2 B#,,2

m,Jno iX,j,k

pXm,J^rst

∈WX^Z

+

C ∈WXJZ

#,$ Œ

∈WXJZ

m,Jno iX,j,k

pXm,J^rno

Œ

#,$

, S#,,2

M 32 M

, h`Š B#,,2

#,$

) M 32 ∀!, 1 ≠ |.|

∈WXJZ

,$ ) + - ∙ 1 − ∑ VS#,,2 E

, yz{ ‰#,2 ‹ ∀!, 1 ≠ |.| 32 M -

(48) (49)

∈WX^Z

, + S#,,2 E

∈WXJZ

[Ž ∀!, 1 ≠ |.| (50)

5.2.3. Simplification for Unidirectional Flow

In the case of segments ! ∈ "  with unidirectional flow, eqs 35-39 are replaced by eqs 51 and 52.

Eq 51 derives from the logic proposition implicit in eq 48, which states that at most one product is entering the segment. Eq 52 translates into at most one product leaving the segment. Note that we

are not assuming the same direction of flow in all segments (sets #$ and # will be empty in

segments with right-to-left flow, while # = #$ = ∅ in segments with left-to-right flow). ,$ , ∑∈W^Z S#,,2 + ∑∈WXJZ S#,,2 M 1 ∀! ∈ "  , 1 ≠ |.| X

,$ , ∑∈W^Y S#,,2 + ∑∈WXJY S#,,2 M 1 ∀! ∈ "  , 1 ≠ |.| X

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5.2.4. Forbidden Product Sequences 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

Castro and Mostafaei19 presented constraints for forbidding specific product sequences when entering a unidirectional segment. These are now generalized for the case of reversible flow.

,$ , Let binary variables S#,,2 and S#,,2 identify the left- and right-most product in segment ! at event

point 1. Clearly, there can be only one such product, leading to the exclusive disjunctions in eqs 5354. The constraints inside the disjunctions state that volume of product  must be greater than a

minimum volume and that the left/right coordinate must be equal to zero or the segment volume, respectively.

,$ S#,,2

 ` gD#,,2 Q #, h ∀! ∈ " $ , 1 ≠ |.| C $ ƒ#,,2 =0 ∈WX , S#,,2

 ` gD#,,2 Q #, h ∀! ∈ " $ , 1 ≠ |.| C  ƒ#,,2 = # ∈WX

(53)

(54)

To prevent forbidden sequence ´-  from happening (´ ∈  ), we must prevent ´ from entering

from the left/right during slot 1, if  is the left/right-most product in segment ! at event point 1, see

eqs 55-56.

,$ ,$ S#,,2 ⟹ ¬S#,´,2 ∀! ∈ " $ ,  ∈ # , ´ ∈  ∩ #$ , 1 ≠ |.|

(55)

, , S#,,2 ⟹ ¬S#,´,2 ∀! ∈ " $ ,  ∈ # , ´ ∈  ∩ # , 1 ≠ |.|

(56)

,$ ∑∈WX S#,,2 = 1 ∀! ∈ " $ , 1 ≠ |.|

(57)

The disjunctions and logic propositions can be reformulated into eqs 57-64.

,$  D#,,2 Q #, S#,,2 ∀! ∈ " $ ,  ∈ # , 1 ≠ |.|

,$ $ ƒ#,,2 M # ∙ (1 − S#,,2 ) ∀! ∈ " $ ,  ∈ # , 1 ≠ |.|

, ∑∈WX S#,,2 = 1 ∀! ∈ " $ , 1 ≠ |.|

,  D#,,2 Q #, S#,,2 ∀! ∈ " $ ,  ∈ # , 1 ≠ |.|

18 Environment ACS Paragon Plus

(58) (59) (60) (61)

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,  ƒ#,,2 Q # S#,,2 ∀! ∈ " $ ,  ∈ # , 1 ≠ |.|

,$ ,$ S#,,2 + S#,´,2 M 1 ∀! ∈ " $ ,  ∈ # , ´ ∈  ∩ #$ , 1 ≠ |.|

, , + S#,´,2 M 1 ∀! ∈ " $ ,  ∈ # , ´ ∈  ∩ # , 1 ≠ |.| S#,,2

6.

(62) (63) (64)

COMPUTATIONAL RESULTS The performance of the new MILP continuous-time scheduling formulation for pipeline systems

with reversible flow and any structure, is now evaluated through the solution of a set of six benchmark problems from the literature. The main goal in this study is to validate the model for a variety of problem features, highlighting its strengths and identifying aspects that can be improved in the future. By selecting makespan minimization as the objective function, we aim to maximize the operating flowrates in the different pipeline segments and hence take full advantage of the pipeline capacity. The results in Table 1 show that makespan can be reduced compared to the values reported in the literature. However, one shouldn’t make conclusions about computational efficiency since the objective function used by previous authors, while often including a makespan minimization term, dealt with cost minimization. Table 1. Features of benchmark problems considered in this work. Makespan (h) Flow Market Reported This Reduction Direction Supply work Motivating This work Tree-like Reversible No 195 Ex1 Ref. 22, Ex. 1 Straight Reversible No 129.00a,b 168.00 -30.2% Ex2 Ref. 22, Ex. 2 Straight Reversible Yes 327.50a,b 310.32 5.2% a,b Ex3 Ref. 22, Ex. 3 Straight Reversible Yes 325.71 310.00 5.1% Ex4 Ref. 15, Ex. 1 Tree-like Unidirectional No 154.17a 138.33 10.3% Ex5 Ref. 15, Ex. 2 Tree-like Unidirectional No 179.98a 162.00 10.0% Ex6 Ref. 20, Ex1 Mesh Unidirectional Yes 179.00a,b 194.29c -8.5% a b Objective function was cost minimization; Makespan term included in objective function; c Found while using different hardware and software. Example

Source

Structure

The model was implemented in GAMS and solved using CPLEX running in parallel deterministic mode using up to eight threads on desktops with solid-state drive running Windows 10, 64-bit operating system. The termination criteria were either a relative optimality tolerance of 10-6 or a maximum wall-time limit of 18,000 CPUs. All computational results but one, are for CPLEX 12.6.3 19 Environment ACS Paragon Plus

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running on a desktop with an Intel i7-6400K (4.0 GHz) processor and 16 GB of RAM. For Ex6, the 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

194.29 h makespan reported in Table 1 (vs. 206.429 h in Table 2), was proven optimal for |.|=12 in

10797 CPUs when using CPLEX 12.7.0 on a desktop with an i7-4790 (3.6 GHz) processor and 8 GB of RAM. 6.1. Performance overview

As mentioned in section 4, the specified number of event points in the grid affects both solution quality and computational performance. It can thus be viewed as a tuning parameter of the proposed formulation. Table 2 shows the value of these two key performance indicators as a function of |.|.

Note that Ex4 is the only one meeting the solution quality termination criterion (normal termination with the same solution for consecutive event points). Thus, makespans lower than the values reported are highly probable for the benchmark problems hitting the maximum computational time limit. It reflects their complexity, with the CPLEX solver, in many cases, only being able to find the first feasible solution after several minutes of computational time. The most interesting problem from a computational point of view is perhaps the reversible flow problem Ex2, since it can be solved to optimality for five settings of |.| greater than 11, a value for which it is integer infeasible.

Table 3 features two rows per problem to show the impact of |.| in problem size and quality of the

linear relaxation. The motivating example and Ex1 have the weakest relaxations, which degrade

slightly with the rise in |.|, and the highest integrality gaps. In terms of system structure, these are

reversible flow problems with nodes not linked to local markets. The simplest tree-like problem,

Ex4, is the tightest with a mere 2.5% integrality gap. All problems feature several hundred binary variables and a few thousand constraints, with problem size increasing modestly with the number of events. We now switch attention to the analysis of the optimal schedules.

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Table 2. Influence of number of event points in computational performance and solution quality (best solution in bold, maximum computational limit in italic). Example |.| Makespan (h) CPUs Motivating 8 Infeasible 28.1 9 210 551 10 205 2152 11 15454 195 12 195a 18000 Ex1 10 Infeasible 475 11 204 10356 12 18000 168b Ex2 11 Infeasible 50.9 12 355 111 13 345 286 14 335.625 591 15 319.405 5852 16 314.652 10209 17 18000 310.323c Ex3 12 Infeasible 406 13 323.33 1975 14 11789 310 d 15 18000 310 Ex4 10 Infeasible 306 11 704 138.333 12 11004 138.333 Ex5 10 Infeasible 1285 11 3126 162 12 164.29e 18000 Ex6 11 Infeasible 581 12 18000 206.429f 13 no solutiong 18000 a Best possible solution (BPS)=145.6; bBPS=90; cBPS=303; dBPS=280; eBPS=145; fBPS=190; g BPS=171.9.

Table 3. Statistics related to problem size

Example |.| LP relaxation (h) Integrality gap Binary variables Total variables Equations Motivating 10 101.67 102% 792 1910 2818 11 101.50 92% 879 2116 3122 Ex1 11 66.375 207% 1019 2535 3891 12 66.343 153% 1120 2782 4271 Ex2 16 260 21% 574 1680 2219 17 260 19% 612 1790 2364 Ex3 14 260 19% 1100 2784 3992 15 260 19% 1184 2994 4293 Ex4 11 135 2.5% 1102 3414 5392 12 135 2.5% 1210 3742 5912 Ex5 11 145 12% 2142 6574 10443 12 145 13% 2352 7206 11451 Ex6a 12 170 21% 1329 4009 6252 a Integrality gap can only be computed for |.|=12, which is the reason for showing a single row. 21 Environment ACS Paragon Plus

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6.2. Straight pipelines with reversible flow 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

Benchmark problems Ex1-Ex3 are taken from Cafaro and Cerdá22. Ex1-Ex2 feature a single pipeline segment with a node on each side. Ex1 deals with nine products and several forbidden sequences, while Ex2 and Ex3 feature just four products with no sequence restrictions. Nevertheless, the latter two are far more challenging since they also involve inventory control of the storage systems linked to the nodes, with refinery inputs at constant rates and outputs to local markets occurring at flowrates lower than pipeline operating flowrates. Ex3 adds an intermediate node compared to Ex2 while keeping product demand over all nodes constant. 6.2.1. Ex1 Ex1 is concerned with a real-world bidirectional pipeline connecting a harbor to an inland refinery4,12. Products P1-P4, available at the left node N1, need to be supplied to the right node N2 in quantities (1800, 3600, 1800, 1800) m3. In turn, node N2 needs to supply (1800, 1800, 3600, 3600) of P5-P8 to N1. The pipeline is initially filled with another product (P9) and the flowrate, in either direction, ranges between [150, 300] (m3/h). To guarantee a feasible solution, the time horizon was

extended from -=144 to 220 h (the idea for increasing the value of - is to make parameter |.| the

sole responsible for an infeasible outcome; while the value of - affects computational performance, typically the lower the better, no tuning was performed).

The best solution found by our model is shown in Figure 8 and has a makespan of 168 h, 30.2% higher than the value reported by Cafaro and Cerdá22. Interestingly, the pipeline is always operating at the maximum flowrate and so the reason for the longer time is due to the pumping of volumes larger than those required to meet product demand (met exactly only for P1, P5, P6 and P8). It is caused by the low number of events (|.|=12) and the restriction of a single product entering and leaving a segment during a time slot. A product with a demand lower than the capacity of the pipeline (7200 m3) requires a minimum of three time slots (the first for injection, the second for reaching the opposite end, and the third for delivery), see for instance P5 in [102, 132] and P6 in [126, 156]. In contrast, the model by Cafaro and Cerdá22, allows a single entering product, to control the segment flowrate, but multiple leaving products per time slot. It prevents rigorously enforcing 22 Environment ACS Paragon Plus

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capacity constraints in receiving storage tanks but can lead to much better schedules using the same 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

number of time slots (called pumping runs22) and to improved computational performance. N1

N2 P1 P2 P3 P4 P5 P6 P7 P8 P9

Time Interval

S1 7200

300 m3/h

[0,24] h

7200

7200

7200

7200

7200

7200

7200

7200

7200

300 m3/h

[24,48]

7200 300 m3/h

[48,72]

7200 300 m3/h

[72,96]

7200 300 m3/h

[96,102]

1800

1800

7200 300 m3/h

[102,108]

5400

1800

1800

1800 300 m3/h

[108,126]

5400

1800

5400

5400 300 m3/h

[126,132]

1800

5400

1800

1800 300 m3/h

[132,150]

5400

1800

5400

5400 300 m3/h

[150,156]

1800

5400

1800

1800 300 m3/h

[156,168]

3600

1800

1800

3600

3600

Figure 8. Best-found schedule for Ex1. Our model cannot handle multiple product deliveries to intermediate nodes (per time slot) for reasons related to the coordinate constraints, but can be adapted to allow it for terminal nodes (by changing some disjunctions from exclusive to inclusive) in cases where storage constraints are not important. This will be the subject of future work. 6.2.2. Ex2 Ex2 involves four products and a single segment with two terminal nodes22. It is a very challenging problem since the transportation schedule must guarantee that the storage levels linked to nodes N1 and N2 are kept within minimum and maximum limits. The tanks are fed by a refinery at a constant rate equal to (100, 150) m3/h for P1-P2 in node N1, and (50, 80) m3/h for P3-P4 (N2), and need to supply (18000, 20000, 23000, 36000) m3 of P1-P4 (N1) and (34000, 40000, 0, 0) (N2) to local markets. Since the maximum supply rate to local markets (200, 250, 100, 150) m3/h is lower than the maximum transportation flowrate, one cannot leave market deliveries to the last moment. Another interesting aspect is that the injection bounds are different between the left-to-right, [100,

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600] m3/h, and right-to-left directions of flow, [50, 400]. To enable finding feasible solutions with 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

lower values of |.|, - was increased from 336 to 360 h.

The best-found solution for Ex2 is given in Figure 9 and corresponds to a makespan of 310.323 h,

a value 5.2% lower than the 327.50 h reported by Cafaro and Cerdá22. The schedule starts with leftto-right flow, interrupted at 93.50 h, when products P1, P2 and P4 in N1 are at their minimum allowed levels (5000 m3 for P1 and P4 and 6000 for P2), see profiles in Figure 10. The optimization decides to keep P2 at a minimum by supplying local markets at the refinery input rate, until 192.47 h. The levels of the other products increase before that, due to the transportation from N2 (right-toleft flow). On the other hand, P4, P3 and P1 reach minimums at N2, with the latter triggering the second flow reversal at the 217.47-hour mark. Interestingly, once 18409 m3 of P1 reach N2, the remaining volume needed by local markets (the schedule ends with P1 in N2 at the minimum, 5000 m3), the direction of flow changes once more to meet the demand of P3 and P4 at N1. Notice that the last pumping run occurs at a flowrate of 150 m3/h, well below the maximum, intriguing considering that we are minimizing makespan. The reason is because this is the maximum supply rate of P4 to local markets, which cannot be anticipated since P4 also ends at the minimum level in N1. Overall, product inventory at the end is much lower than at the beginning, with critical levels reached in N2 for all products.

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1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

Time Interval

N2 P1 P2 P3 P4

Market Deliveries

S1

Market Deliveries

10000 292.6 m3/h

[0,34.18] h

126.3

5000

10000

5000

20000

5000

8543.9

10000

10000

10000

20000

6666.7 8333.3

10000

10000

4166.7

10000

5591.4

2329.7

600 m3/h 3758.1

[34.18,67.51]

3333.3

600 m3/h

[67.51,84.18]

2500

10000

[84.18,93.50]

1397.8

5591.4

[93.50,111.99]

3698.9 2774.2 1666.7

600 m3/h 400 m3/h 2602.2

7397.8

7397.8

7397.8

4623.7

2602.2

1626.3

7397.8

4623.7

400 m3/h

[111.99,118.50]

1301.1

975.8

2602.2

[118.50,136.99]

2397.8 2774.2 1849.5

7397.8

7397.8

2602.2 400 m3/h 10000 400 m3/h

[136.99,170.70]

5056.5

5056.5

13484

[170.70,192.47]

3266.1 2177.4 3266.1

7225.8

3371

10000

13484

311.8

331.9 m3/h 2774.2

1559.1

7225.8

7225.8 400 m3/h

[192.47,199.41]

1040.3

2774.2

[199.41,217.47]

1806.5 2709.7

7225.8

[217.47,251.56]

3408.6 5112.9

7225.8

2774.2

2774.2 400 m3/h

10000

7225.8

3612.9

540.1 m3/h 18409

18409

10000

6817.2

400 m3/h

[251.56,260.00]

1266.1

3376.3

1655.9 2483.9

6623.7

91.4

354.8

6623.7

3376.3

3376.3

1688.2

6623.7

3311.8

3376.3

3236.6

2516.1

3354.8 4193.5

400 m3/h

[260.00,276.56]

3376.3

6623.7 198.7 m3/h

[276.56,293.55]

3397.8

[293.55,310.32]

3354.8

1698.9 2548.4

3376.3

1677.4 2516.1

2516.1

10000 150 m3/h

1129

7483.9

2516.1

Figure 9. Best-found schedule for Ex2. (m3) 30000

(m3) 30000

P1

P2

P3

Node N1

P4

P1

25000

25000

20000

20000

15000

15000

10000

10000

5000 0

50

100

150

200

250

5000 300(h) 0

50

P2

100

P3

150

Node N2

P4

200

250

300(h)

Figure 10. Inventory profiles from best-found schedule for Ex2. 6.2.3. Ex3 Ex3 is a variant of Ex2 created by Cafaro and Cerdá22 to try to reduce the operating costs by means of a new node placed in the middle of the pipeline. Total demand is the same, but part of the demand for node N1 (10000 m3 of P3) and the right-most node (now named N3), 14000 of P1, has been reallocated to N2. In ref. 22, the middle node is an output node, while in this work, it is defined as a dual-purpose node to give more flexibility to the system. Furthermore, the two segments comprising the pipeline do not always need to operate in the same direction. Due to the increase in the number of segments and nodes, problem size roughly doubles (check Table 3), making it far more complex than Ex2. Better solutions are found for a given number of event points, with the optimal schedule being obtained for |.|=14, see Figure 11. Interestingly, we 25 Environment ACS Paragon Plus

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Page 26 of 42

could only reduce the makespan by less than 20 minutes (compared to Figure 10), to 310 h, a value 5.1% lower than the 325.71 h reported in ref. 22. In the best-found schedule, we can see that the system takes full advantage of the storage tanks of N2. They receive an amount of P1 greater than the demand (19250 m3 vs. 14000), which is partly injected back into the pipeline during interval [260, 287.50] h to help meet the last 5000 m3 of P3 in N1. This is the second time segments S1 and S2 operate independently, with N2 feeding N1, and N3 feeding N2. The first, is in interval [95, 111.67], where they operate in opposite directions to move the full contents of the pipeline (10000 m3 of P1) into N2, replacing it with P3. Once again, the market supply rate is the limiting aspect for makespan, with S1 operating at the minimum rate in the last slot and S2 being idle. It is also reflected in the inventory profiles of Figure 12 (products P3 and P4 in N1, and P3 in N2, finish at their minimum levels). N1

Time Interval

N3

N2

S1

Market Deliveries

S2

5000 600

[0,8.33] h

1666.7

1250

600

5000

[8.33,33.33]

3750

5000

5000

20000

5000

5000 3666.7

7000

12000

5000

3333.3

10000

3000

5000

240 m3/h 2500 400 m3/h

5000

2500

[111.67,124.17]

2500

1250

5000

1875

3000

1250

[124.17,136.67]

1250

1875

1250

[136.67,200.00]

6333.3

2625

5500

[200.00,222.50]

2250

5000

5000

20000

6666.7 8333.3

5000

5000

1666.7 2083.3

5000

5000

9500

16000

5000

3375

5000

5000

5000

5000

5000

5000 1250

[260.00,287.50]

6875

2750

4125

5000

5000 100 m3/h

[287.50,310.00]

2250

3375

5000

182 m3/h

2250

4500

5000

3125

5000

3125

16000

5833.3

222 m3/h 5000

5000

5000

4166.7

253 m3/h 5000

213 m3/h

3000

5000

1000

400 m3/h

8000

5000

3750

182 m3/h

5000

5625

5000

5000

5000 5000

133 m3/h

4000

400 m3/h

222 m3/h

2750

6250

300 m3/h

253 m3/h

[222.50,260.00]

5000

250 m3/h

2000

300 m3/h

[95.00,111.67]

5000

600 m3/h

5000 600 m3/h

[75.00,95.00]

1666.7 2083.3

600 m3/h 5000

600 m3/h 1250

5000

5000 200 m3/h

600 m3/h

[66.67,75.00]

m3/h

5000 200 m3/h

[33.33, 66.67]

Market Deliveries

5000

m3/h

2250

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

2750

5000

5000

2250

P1 P2 P3 P4

5000

Figure 11. Best-found schedule for Ex3. (m3) 30000

(m3) 30000

P1

P2

P3

Node N1

P4

(m3) 30000

P1

P2

P3

Node N2

P4

25000

25000

25000

20000

20000

20000

15000

15000

15000

10000

10000

10000

5000 0

50

100

150

200

250

5000 300(h) 0

50

100

150

200

250

5000 300(h) 0

Figure 12. Inventory profiles from best-found schedule for Ex3. 26 Environment ACS Paragon Plus

P1

50

P2

100

P3

150

Node N3

P4

200

250

300(h)

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Industrial & Engineering Chemistry Research

6.3. Tree-like pipelines with unidirectional flow 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

Benchmark problems Ex4 and Ex5 deal with tree-like structures consisting of a mainline and secondary lines emerging from it15. There is one input node on the left end, and the flow to the intermediate and the multiple terminal output nodes is unidirectional. The problems have been solved by Mostafaei et al.15 for the objective of cost minimization, using a batch-centric formulation that, unlike the current formulation, cannot handle systems with branches on secondary lines (a batch-centric formulation for multilevel tree-like structures can be found in the work by Cafaro and Cerdá37). The reported makespans are 10% higher than the values shown in Figure 13 and Figure 14. Both problems feature forbidden product sequences.

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S3 1000

3000

2000

2000

2000 2000

1000

2000

2000

2000

3000

2000

4000

1000

66.7 m3/h 2000

3000

200 m3/h 3000

109.1 m3/h 2000

120 m3/h 2000

1000

4000

2000 1000

1000

1000 60 m3/h 1000

1000

1000

1000

2000

200 m3/h 3000

2000

[128.33,138.33]

2000

2000

3000

200 m3/h 2000

100 m3/h 2000

2000

2000

1000

1000

50 m3/h

100 m3/h 3000

4000 100 m3/h 1000

1000

1000

1000

4000

200 m3/h

133.3 m3/h

3000 50 m3/h

[108.33,128.33]

54.5 m3/h 3000

60 m3/h 2000

1000

3000

66.7 m3/h

[93.33,108.33]

2000

2000

1000

1666.7

3666.7

200 m3/h

1333.3

[76.67,93.33]

3000

1000

2000

54.5 m3/h

3333.3

[58.33,76.67]

200 m3/h

1000

1000

1000

1000

3000

120 m3/h 2000

1000

1000

3000

100 m3/h 2000

1000

1000

2000

1000

2000

66.7 m3/h

[43.33,58.33]

1000

2000 1000

1000

N3

2000

1000

N5 S4

1000

200 m3/h

S2

1000

200 m3/h

N4

2000

1000

150 m3/h 1000

1000

100 m3/h 2000

2000

[26.67,43.33]

3000

200 m3/h

1000

[16.67,26.67]

1000

2000

[10,16.67]

3000

3333.3

[0,10] h

N2

1000

S1

Time Interval

P1 P2 P3 P4 P5 P6

1333.3

N1

2000

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

Figure 13. Optimal schedule for Ex4. In Figure 13, one can see that the P1-P5, P1-P6, P2-P4, P2-P5, P4-P2, P5-P1, P5-P2 and P6-P1 forbidden sequences for Ex4, enforced at the entrance of a segment, are respected. Notice that the volume of P2 initially in segment S3 must wait for all P4 in segments S1 and S2 to be transferred to nodes N2 and segment S4, before being delivered to N4 by means of P1 (during [43.33, 76.67] h). Another interesting observation is that the total supply of P1 to node N2 is higher than the 3000 m3 demand (for all other products and nodes, the delivered volume is equal to the demand). It is because the minimum delivery rate to N2 was set equal to the minimum flowrate in segment S1 (80 m3/h). A 28 Environment ACS Paragon Plus

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feature shared with the model of Mostafaei et al.15 is the simultaneous delivery to multiple output nodes, which occurs during intervals [58.33, 93.33] h and [108.33, 128.33] for nodes N2, N4 and N5. Finally, while 5000 m3 of P6 are initially available at N1, the optimization decides not to use it, because (i) the demand of P6 in all output nodes is equal to zero; and (ii) there are no productdependent pumping costs (unlike in ref. 15, where P6 is the cheapest product to pump and so it enters the pipeline towards the end). S2

2000

2500

N2

N4

4000

S1

2000

2000

7000

[0,20] h

4000

4000

2000

100 m3/h 2000 4000

2000

2000

6000

300 m3/h 2000

2000

2000

200 m3/h 2500

2000 4000

4000

200 m3/h

200

2500

2000

2000 4000

2000

2000

2000

200 m3/h

[50,60]

N8

2000

2000

2000 50 m3/h

1000

2000 100 m3/h

1000

2000

2000

4000

200 m3/h

m3/h

1000

S7

2000

2000

2000

200 m3/h

[30,50]

N7

2000

2500

200 m3/h 2000

N6

100 m3/h 1000

2500 200 m3/h

[20,30]

1000

S6

50 m3/h 350 m3/h 2000

2000

S3

S5 2000

1000

Time Interval

N5

S4 N3

1000

P1 P2 P3 P4 P5 P6

2000

N1

2000 100 m3/h

2000

2000

2000

2000

2000

2000

200 m3/h

2000

2500 4000

4000

2000

[80,90]

2000

2000

200 m3/h

100 m3/h 2500

200 m3/h 2000

2000

350

m3/h

3000

[60,80]

7000

100 m3/h

4000

2000

2000

200 m3/h

2000

2000

2000

2000

2000

2000

2000

2000

2000

2000

2000

2000

2000

2000

2000

2000

2000

200 m3/h 2500 4000

4000

2000 100 m3/h

2500 4000

2000

2000

200 m3/h

200 m3/h

[120,140]

6500

125 m3/h

100 m3/h 2500

325 m3/h 2000

4000

2000

2500 4000

100 m3/h

4000

68.2 m3/h 350 m3/h 2000

2000

2000

200 m3/h

[140,162]

2000

200 m3/h 2000

2000

[110,120]

2000

200 m3/h

50 m3/h 2500 4000

2200 100 m3/h

1100

900

1100 50 m3/h

900

1500 1100

Figure 14. Best-found schedule for Ex5.

29 Environment ACS Paragon Plus

1100

200 m3/h 2000

1100

[90,110]

4000

100 m3/h

7700

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

2000 2000

2000 2000

2000

Industrial & Engineering Chemistry Research

With seven segments and eight nodes, Ex5 is a more complex problem, which is reflected in a 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

doubling of the number of binary variables and constraints (check Table 3). The forbidden sequences are now P1-P3, P2-P5, P3-P1, P3-P5, P4-P6, P5-P2, P5-P3 and P6-P4 and there are five simultaneous deliveries to output nodes N2, N3, N6-N8 in interval [0, 20] h, see Figure 14. Supply exceeds demand again, now by 100 m3, for product P1 in nodes N5 and N7, to respect the minimum flowrate of 50 m3/h in segments S4 and S6 during the last slot.

The best-found solutions for Ex4 and Ex5 were found for |.|=11 event points. Mostafaei et al.15

solve another problem (example 3) with eight segments and nine nodes that turned out to be too complex to solve by the proposed formulation. As an indication, a minimum of 16 events are required just to meet the demand of the nodes further away from the input node (N5 and N6), and it took 2014 CPUs to find a makespan of 88.67 h. The demand of N4 was also met with 16 events but the computational time surpassed one hour (more event points are needed for the remaining eleven product-node deliveries). The explanation for the better performance of the model by Mostafaei et al.15 can be found in the fewer event points needed to represent a schedule (13) and is a direct consequence of batch-centric models allowing multiple products to leave a segment during a time slot, instead of a single product by the proposed product-centric model (a detailed comparison between these two type of models for straight pipelines can be found in Castro and Mostafaei19). It is an indication that models tailored to a specific pipeline topology may be considerably more efficient computationally. 6.4. Mesh structure with unidirectional flow The last benchmark problem is taken from Cafaro and Cerdá20 and deals with a mesh structure with six segments, seven nodes and unidirectional flow, see Figure 15. There are four products involved and sequences P3-P4 and P4-P3 are forbidden. Node N1 is a source of products P1-P3 while N2 supplies P2 and P4. Both nodes receive no external input from refineries and so the amounts available at the beginning of the time horizon are sufficient to meet product demand in nodes N3, N5-N7. These nodes supply local markets at a maximum rate of 700 m3/h.

30 Environment ACS Paragon Plus

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Industrial & Engineering Chemistry Research P1 P2 P3 P4

N1

N3

S1 15000

10000

30000

20000

25000

S6 N7

3500

10000

20000 7000

1000 m3/h 50000

7000

1000 m3/h

10000

20000 7000 20000

20000

15000

10000

7000

10000

20000

1000

5000

25000

800 m3/h

9000 10000

20000

3500

1000 m3/h 20000

20000

25000

30000

1000

20000 17500

20000

40000

6000

10000

25000 800 m3/h

50000

1000 m3/h

17500

50000

15000

800 m3/h 20000

50000

988.2 m3/h

30000

20000 21250

988.2 m3/h 10000

800 m3/h 40000

20000

30000

8750

20000

40000 800 m3/h

800 m3/h 10000

20000

15000

17143

32857 15000

800 m3/h 50000

5750

27143

8750

15000

30000

800 m3/h 17143

10000

50000 10000

1250

800 m3/h

21250

20000

8750

50000

10000

50000 30000

[160.36,172.86]

17143

7000 50000

25000

800 m3/h

30000

30000

1000 m3/h 20000

10000

10000

10000

1000 m3/h

50000

[172.86,194.29]

4250

1000 m3/h 20000

1000 m3/h

40000

20000

50000

10000

50000

1000 m3/h

[130,160.36]

14000

1000 m3/h 20000

1000 m3/h

[105,130]

7000

10000

40000

20000

25000

1000 m3/h

30000

30000

20000 10000 25000

20000

50000

[80,105]

25000

1000 m3/h

1000 m3/h

[70,80]

30000

10000

20000

30000

20000

1000 m3/h

7000

50000

1000 m3/h

1000 m3/h 10000

20000

10000

20000

30000

7000

10000

25000

40000

20000

32857

17143

10000

[50,70]

10000

2000

1000 m3/h 10000

30000

20000

[40,50]

20000

10000

10000

30000

5000

5000 20000

10000

20000

10000

10000

40000

17500 40000

20000 1500

1000 m3/h 10000

1000 m3/h

20000

10000

10000

10000

10000

40000

20000

17143

800 m3/h

20000

25000

20000

20000

35000

20000

15000 1000 m3/h 20000

10000

10000 5000

30000

25000

1000 m3/h 20000

5000

5000 20000 10000

15000

N6

30000

[30,40]

35000

S5

30000

[5,30]

15000

20000

N5

S4

S3

N2

[0,5] h

N4

S2

35000

10000

Time Interval

17143

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

Figure 15. Best-found schedule for Ex6. Node N4 is an intermediate dual purpose node connecting four segments, S2-S5. In Cafaro and Cerdá20, node N4 forces products arriving from S2 and S3 to wait for one time slot before being injected in segments S4-S5. Such conservative constraint is relaxed in this work and so we assume 31 Environment ACS Paragon Plus

Industrial & Engineering Chemistry Research

that node N4, besides being able to inject product into segments S4 and S5, has a valve system that 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

allows for different connections between segments S2-S3 to S4-S5. While the formulation makes it possible for a segment (e.g. S2) to transfer a product to segments S4 and S5 simultaneously, it is not observed in the schedule due to narrow flowrate bounds, [800, 1000] m3/h in all segments. Segment S2 is connected to S5 during [30, 50] h and [172.86, 194.29] and to S4 during [50, 70] and [80, 160.36]. We enforce the same bounds on the nodes inlet and outlet flowrates, which prevents alternative destinations on a branch to be active at the same time (e.g. N3 and the outlet of S2, N6 and N7). The exception occurs if intermediate nodes N3 and N6, defined as dual purpose to give more flexibility to the system (single purpose in ref. 20), receive one product and ship another, see N3 in Figure 15 and slot [50, 70] h. (m3)

(m3)

35000

35000

P1

P2

P3

30000

Node N3

30000

25000

25000

20000

20000

15000

15000

10000

10000

5000

5000

0 0

50

100

150

(m3) 25000

(h)

P1

P2

P3

P4

0 200 0

Node N5

50

100

150

(m3) 25000

P1

P2

P3

P4

Node N6

20000

20000

15000

15000

10000

10000

5000

5000

0 0

50

100

150

(h)

0 200 0

P1

P2

50

P3

P4

100

(h) 200

Node N7

150

(h)

200

Figure 16. Inventory profiles for Ex6. Ex6 is the most complex of all benchmark problems solved. It becomes feasible for |.|=12 event

points but five hours of computational time are not enough to prove optimality (gap=8.6%).

Increasing |.| to 13 leads to no feasible solution in the same computational time, recall Table 2. It is interesting to observe in the schedule in Figure 15 that while all four products are initially in the

pipeline, the optimization drives two of them out towards the end, to reduce the number of slots required to move the products between segments. Segment flowrates are at the minimum in the last two slots, indicating that the bottleneck for makespan minimization lies with product delivery to 32 Environment ACS Paragon Plus

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local markets, in this case P1 to N5. Notice in the inventory profiles in Figure 16 that P1 in N5 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

reaches the minimum level of 5000 m3 at hour 130, having to wait for the start of the 30000 m3 delivery (arriving at 988.2 m3/h) to start shipping to local markets (at 700 m3/h). Product P2 in node N7 is at the minimum level during a long period [80, 172.86] h, having to wait for the last delivery from segment S6 to meet the final 15000 m3 market demand for a total of 40000 m3. Cafaro and Cerdá20 report a makespan of 179 h for Ex6, 15.29 h shorter than our best-found solution. However, upon careful examination of Fig. 7 in ref. 20, one finds that some constraints are not rigorously enforced by their formulation. The first issue, easier to spot, is related to the minimum flowrates of 800 m3/h. Cafaro and Cerdá20 divide the system into lines connecting the main nodes, which may have intermediate nodes. To be more specific, whereas in our work there are a total of four segments connecting nodes N1 to N4 (S1-S2) and N4 to N7 (S5-S6), they correspond to two lines (‘/ and ‘’ ) in Cafaro and Cerdá20. The

consequence seems to be that flowrate constraints are relaxed in the part of the line after the

intermediate nodes, i.e. in segments S2 and S6, since one can compute flowrates of 583 m3/h for segment S2 during [0, 60] h, and 588 and 183 m3/h for S6 during [133, 150] and [150, 179],

respectively. Interestingly, the first part of line ‘’ (S5) already exhibits a violated flowrate (586

m3/h) in the last slot. One possible explanation, provided by one of the reviewers, is that not all injections performed during a time slot are assumed20 to last the full duration of the slot. The second issue is related to the delivery to local markets and can be found after subdividing the intervals of the schedule in Fig. 7 of ref. 20 so that a single product is delivered to node N5. It leads to events {0, 35, 60, 105, 110, 133, 150, 163.5, 179} (h). While the 80000 m3 delivery of P1 to local markets can be met respecting the 700 m3/h maximum flowrate and minimum capacity constraints,

the same is not true for the 90000 m3 delivery of P2. In N5, P2 is initially at the minimum (10000 m3, see Figure 16) and only begins to arrive from line Ԡ (S4) at hour 35. Subsequent arrivals make it

possible to ship at the maximum rate up to hour 133. The inventory at that point is equal to 16400 m3 and so one can only ship 6400 m3 until the last delivery from S4 begins. It occurs at 163.5 h, being

33 Environment ACS Paragon Plus

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still possible to ship 10850 m3 to local markets. Unfortunately, at the end of the time horizon, we 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

only managed to ship a total of 85850 m3, 4150 m3 short of the target. 7.

CONCLUSIONS This paper has presented what is perhaps the most general formulation for integrated scheduling of

pipeline systems and associated storage tanks. It views the system as a network of segments connecting different types of nodes and allows the movement of products in both directions. Material transfer from segments to nodes is triggered by the left or right coordinates, which precisely locate all product batches inside the pipeline. Still, no batches are explicitly defined, being this classified as a product-centric formulation. Its main limitation is that only one batch per product is permitted inside a segment, a direct consequence of resetting the left/right coordinate only after the complete product volume exits on the right/left, enabling a new batch to enter on the next pumping run on the left/right. Forbidden product sequences are rigorously enforced on entry. The mixed-integer linear programming formulation relies on a continuous-time (and volume) representation that divides the time horizon into slots of unknown duration. The continuous movement of materials inside the pipeline can be characterized by segment-dependent flowrates but these are not linked to model variables, to preserve linearity. Instead, they are subject to given lower and upper bounds. By assuming a constant flowrate throughout a slot duration, it is possible to rigorously enforce capacity limits in storage tanks with multiple inputs and outputs. External inputs from refineries were assumed constant throughout the time horizon but the formulation can easily be adapted to handle piecewise constant external flows. This will however increase the number of slots required to represent a schedule, a key performance indicator. Frequently changing profiles are better handled by a discrete-time formulation and so are time-dependent electricity and inventory costs. Minor changes are needed to switch from continuous to discrete time, which will be the subject of future work. The proposed formulation has been validated by solving a motivating example and six benchmark problems from the literature, covering a variety of configurations. Highlights compared to recent formulations include the ability to handle tree-like networks with consecutive branches, for 34 Environment ACS Paragon Plus

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intermediate nodes to act as dual purpose in mesh structures, and the more rigorous handling of 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

flowrate bounds in segments and of minimum levels in storage tanks serving local markets. Still, other formulations may be computationally more efficient for specific configurations, specifically formulations allowing multiple products to enter a terminal node during a slot, in cases where inventory constraints are not relevant. ACKNOWLEGMENT Financial support from Fundação para a Ciência e Tecnologia through projects IF/00781/2013 and UID/MAT/04561/2013. NOMENCLATURE

Sets/Indices

/ = nodes  U = dual purpose nodes  R = single purpose input nodes  > = junction nodes   = non-junction nodes supplying local markets   = intermediate nodes  T = single purpose output nodes   = non-junction nodes receiving material from a refinery  : = terminal nodes / = products  = products that can appear in node   = products that cannot enter a segment after  # = products that can appear in segment ! #$ = products that can enter segment ! through its left end #$ = products that can leave segment ! through its left end # = products that can enter segment ! through its right end # = products that can leave segment ! through its right end "/! = pipeline segments " $ = segments that can have left-to-right direction of flow "$ = segment whose left end is connected to node  " $ = segments that can have right-to-left direction of flow "  = segments that can reverse flow direction " = segment whose right end is connected to node  "  = segments restricted to a single flow direction ./1 = event points of the time grid

Parameters

$, %#, = left coordinate of product  in segment ! at the start of time horizon (m3) , %#, = right coordinate of product  in segment ! at the start of time horizon (m3)

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,{ y , = demand at node  for product  (m3) , = maximum volume entering/leaving the segment from/to node  (m3) , = minimum volume entering/leaving the segment from/to node  (m3) #, = maximum volume into segment ! during a time slot (m3) #, = minimum volume into segment ! during a time slot (m3) - = time horizon (h) , = initial volume of product  in storage system of node  (m3) , , , = maximum volume of product  in storage system of node  (m3) , = minimum volume of product  in storage system of node  (m3) , # = volume of pipeline segment ! (m3) , #, = initial volume of product  in segment ! (m3) , = maximum flowrate of product  from storage system of node  to local markets (m3/h) , , , = flowrate of product  from refinery to storage system of node  (m3/h) , , = maximum flowrate of product  entering the pipeline from node  (m3/h) , , = minimum flowrate of product  entering the pipeline from node  (m3/h) , = maximum flowrate of product  leaving the pipeline into node  (m3/h) , , , = minimum flowrate of product  leaving the pipeline into node  (m3/h) #,$ = maximum flowrate in segment ! for left-to-right direction of flow (m3/h) #,$ = minimum flowrate in segment ! for left-to-right direction of flow (m3/h) #,$ = maximum flowrate in segment ! for right-to-left direction of flow (m3/h) #,$ = minimum flowrate in segment ! for right-to-left direction of flow (m3/h)

Variables

, S,2 = binary variable indicating no product injected in pipeline by node  during slot 1 , yz{ S,2 = binary variable indicating node  is not receiving neither injecting products during slot 1 , S,,2 = binary variable indicating node  is sending product  to the pipeline during slot 1 , S,,2 = binary variable indicating node  is receiving product  from the pipeline during slot 1 ,# S#,,2 = binary variable indicating product  is inside segment ! at event point 1 ,$ S#,,2 = binary variable indicating  is the left-most product in segment ! at event point 1 ,$ S#,,2 = binary variable indicating product  is entering segment ! on the left during slot 1 ,$  S#,,2 = binary variable indicating  is not entering/leaving segment ! on the left during slot 1 ,$ S#,,2 = binary variable indicating product  is leaving segment ! on the left during slot 1 , S#,,2 = binary variable indicating  is the right-most product in segment ! at event point 1 , S#,,2 = binary variable indicating product  is entering segment ! on the right during slot 1 ,  S#,,2 = binary variable indicating  is not entering/leaving segment ! on the right during slot 1 , S#,,2 = binary variable indicating product  is leaving segment ! on the right during slot 1

, yz{ ‰#,2 = binary variable indicating segment ! is idle during slot 1 ,$ ‰#,2 = binary variable indicating segment ! has left-to-right flow during slot 1 ,$ = binary variable indicating segment ! has right-to-left flow during slot 1 ‰#,2 $ ƒ#,,2 = left coordinate of product  in segment ! at event point 1 (m3) $, ƒ#,,2 = left coordinate of product  in segment ! at the end of slot 1 (m3)  ƒ#,,2 = right coordinate of product  in segment ! at event point 1 (m3) , ƒ#,,2 = right coordinate of product  in segment ! at the end of slot 1 (m3) „ ƒ#,,2 = resets to zero coordinates of product  in segment ! at event point 1 (m3)

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, B,,2 = volume of product  supplied to local market of node  during slot 1 (m3)

, B,,2 = volume of product  injected from node  into the pipeline during slot 1 (m3) , B,,2 = volume of product  leaving the pipeline into node  during slot 1 (m3) ,$ B#,,2 = volume of product  entering segment ! through its left during slot 1 (m3) ,$ B#,,2 = volume of product  leaving segment ! through its left during slot 1 (m3) , B#,,2 = volume of product  entering segment ! through its right during slot 1 (m3) , B#,,2 = volume of product  leaving segment ! through its right during slot 1 (m3) 32 = duration of time slot 1 (h) .2 = time of event point 1 (h)  D,,2 = volume of product  in storage system of node  at event point 1 (m3)  = volume in segment ! of product  at event point 1 (m3) D#,,2

References

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(34) Castro, P. M; Marques I. Operating Room Scheduling with Generalized Disjunctive 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

Programming. Comp. Oper. Res. 2015, 64, 262-273. (35) Drouven, M. G.; Grossmann, I. E. Multi-Period Planning, Design, and Strategic Models for Long- Term, Quality-Sensitive Shale Gas Development. AIChE J. 2016, 62, 2296–2323. (36) Rodriguez, M. A.; Montagna, J. M.; Vecchietti, A.; Corsano, G. Generalized disjunctive programming model for the multi-period production planning optimization: an application in a polyurethane foam manufacturing plant. Comput. Chem. Eng. 2017, 103, 69-80. (37) Cafaro, D. C.; Cerdá, J. Optimal Scheduling of Multi-Level Tree-Structure Pipeline Networks. In Computer-Aided Chemical Engineering, Vol. 29 (2011). Editors: E. N. Pistikopoulos, M.C. Georgiadis, A.C. Kokossis, 980-984.

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