Standard states for water equilibrium (the authors reply) - Journal of

For the purposes of comparison only the unconventionally derived Ka values should be used to compare equilibrium constants for other acids to determin...
0 downloads 0 Views 1MB Size
water and its conjugates means that you must remember to include the activity of water and correctly decide to which standard state water must be referred for each of its several possible roles. If you want to evaluate the competition between water and some other acid for an added base, then the effective acidity of each acid is the product of its "intrinsic" acidity and its activity in solution. For water K ~ ~ ~ ~ ~ , (=H1 ,. O 8 10-I= )~ x 55.3 = L O X 10-l4 That is, for purposes of predicting the competition between water and another acid for an added base, the effective acidity of the water is correctly described by K,. Similarly, a base added to aqueous solutions containing H30t is in competition with water for protons from H30t. The water (which is the conjugate base of H30+)is present at an activity of 55.3 (if you are going to use the intrinsic acidity of H30+).Consequentlythe effective acidity of H30+ is reduced to

The "intrinsic" acidity of the H30+ion also presents pedagogic problems. It is difficult to explain to students that a process that involves no net change can have an equilibrium constant other than unity and thus a finite standard free energy change. Moreover the 55.3 value of the equilibrium constant appears to have little to do with the acidity of H30' but rather to be an artifact of two different standard states for water. We believe that the high probability of confusion and error inherent in using two different standard states for water far outweighs any advantage of "correctly" representing the intrinsic acidity and basicity of water. We would be less inclined to argue if it were proposed to refer water to a 1.0 m standard state at all times. Doing so would reduce all acidity and basicity constants by a factor of 55.3 and the "intrinsic" acidity constant for water would be equivalent to KJ(55.3)'. Thus the intrinsic activity of water would be seen to he less than that of alcohols (although the effective acidity of water in dilute aqueous solutions would be greater as a result of its high activity). However, the acidity constant for H30+would be unity on this scale (as it should be for an exchange process). W. George Baldwin C. Eugene Burchill

University of Manitoba Winnipeg, ME,Canada R3T 2V1 To the Editor: Baldwin and Burchill have misinterpreted the primary point of our previous article. We do not advocate the universal adontion of the K. values for water and the hvdronium ion derived in our paper. As correctly stated by Baldwin and Rurchill. these values use an unconventional standard state fo; water that results in equilibrium constants inconsistent with equilibrium constants derived using the conventional standard state. We agree that the use of two different standard states for water remesent an undesirable standard with concomitant confuskn and increased likelihood of error in usina these constants. While we do not advocate the adoption of the equilibrium constants derived in our article, we still feel these K's give a better indication of the "intrinsic" acidity of water and the hydronium ion than the conventionally derived values. The primary point of our paper, as stated in the title, is that for comparison with other acids, the unconventionally derived K. values give a better indication of the fundamental acidity of water and the hydronium ion, and for pur-

256

Journal of Chemical Education

poses of comparison only, it is these K, values that should be used to compare to equilibrium constants for other acids to determine relative acid strengths. Mark L. Campbell Boyd A. Waite

United States Naval Academy Annapolis, MD 21402

The Use of Equilibrium Notation in Listings of Standard Potentials

To the Editor: In a recent letter by Obline (1990,67, 184) an objection was raised against the use of equilibrium notation (with the double arrow: 5 as distinct from the single one: +) in tables of standard electrode potentials. I do not share this obiection: in my opinion, the real difficulty is due to the convention thai half-reactions must he written as reductions if the kfiven potential is to be called a (standard]electrode potential. his rule is confusing for two reasons. In the f r s t place it should not matter in which direction a chemical equilibrium equation is written. According to thermodynamics, once the system is in equilibrium neither reduction nor oxidation take place anymore. In a kinetic sense oxidation and reduction are proceeding in opposite directions in equal proportions and at an equal rate. The conclusion is the same:

are equivalent notations for the same equilibrium state. In the second place the definition of the electrode potential does not refer at all to reduction or oxidation processes. The electrode potential of a certain electrode is defmed as the cell potential of a symbolic electrochemical cell with the electrode in question placed on the right-hand side and a standard hydrogen electrode on the left-hand side. The cell potential is by definition the electric potential of the right electrode minus the electric potential of the left electrode, provided the measurement is performed in such a way that no electric current is gemmted through th.e cell. This last condition ensures that the whole cell is in eledrochemical equilibrium. Strictly speaking with a cell in this state it is not possible to refer to cathode (where reduction must occur) and anode (where oxidation must occur): The cathode~anodetermmology has to be reserved for galvanic cells (produonr!electric enerw) and electrolvtic cells (consuming electric energy), where the electriccurrent has a nonzero value by definition. For example consider the following cell: Pt, Hz (1atm)l H' (a= 1.0 M)I I c$+,~ 0HzO~I Cu(s) ~I Pt . The relevant half-reactions are on the left side: 2H' (aq)+ 24

5 H (g)

and on the right side:

cu2+(aq)+ 2% 5 Cu(4 The electrochemical cell reaction is 2H+(aq)+ Cu(s) + 2el f Hz(g)+ CU" (aq)+ 29., In these equilibrium equations care has been taken to ensure that the electrons in their different states are ex-