Relative Weights of Phases Present in a Heterogeneous System at

Only one of the more familiar textbooks of physical lOODz - ADS - lO0Az + DAz = IWA'y - DA'y - IOODy + chemistry1 gives a proof of this relation and t...
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Relative Weights of Phases Present in a Heterogeneous System at Equilibrium W. M. SPICER and J. S. METCALF Georgia School o j Technology, Atlanta, Georgia

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HEN the temperature and composition of a system are such that two phases are present a t equilibrium, both the composition and relative weights of the bases can be obtained from the tie lines. For example, consider the system of two components, B and C, as represented in the figure. A system a t temperature TI composed of D per cent B consists a t equilibrium of two phases; the "C" phase containing A per cent B and the UBW phase containing A ' per cent B. Furthermore, Weight of "B" Phase - Length A D Weight of "C" Phase Length DA'

(1)

Only one of the more familiar textbooks of physical chemistry1 gives a proof of this relation and this one for the special case where one phase is a pure component. Some books state, "It can be shown . . ," some say, "It is easy to show . . . ," and others simply state the relation as a fact. The proof of this proposition is neither so obvious nor so difficult that i t should be omitted. A proof follows. Notice that

Multiplying (2) by lOOD and (3)by 100 (100 - D) yields (100 - A')Dy (100

+ (100 - A)Dz = (100 - D)Dw

- D)A1y + (100 - D)Az

=

(100

- D)Dw

(100

- A W Y + (100 - AIDS = (100 - DM'Y + (100 -

(100 - A)Dz

- (100 - D)Az = (100 - D)A1y - (100 - A')Dy

(7)

lOODz - ADS A'Dy

- lO0Az + DAz = IWA'y

- DA'y - IOODy

or Weight of "B" layer - Length AD Weight of "C" layer Length DA'

Assume u = Total weight of mixture y = The weight of "B" layer z = The weight of "C" layer

Then

+ wt. of C i n "C"

layer = total weight Temp

and similarily wt. of B in "B" layer of B

+ wt. of B in "C"

layer

=

total weight

I MILLARD, "Physical~hemi~try for colleges." 5th ed., McGrawHill Book Co., New York, 1941, p. 382.

(6)

on rearranging

= Percent B in "B" layer = Per cent B in "C" layer = Per cent B in total mixture

wt. of C i n "B" layer of C

(5)

Then, from (4) and (5)

.

A' A D

(4)

+ (8)